16x^2+180=x

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Solution for 16x^2+180=x equation: 



16x^2+180=x

We move all terms to the left:

16x^2+180-(x)=0

We add all the numbers together, and all the variables

16x^2-1x+180=0

a = 16; b = -1; c = +180;
Δ = b2-4ac
Δ = -12-4·16·180
Δ = -11519
Delta is less than zero, so there is no solution for the equation

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